A logarithm answers the question:
"To what power must I raise a number (called the base) to get another number?"
$$
\log_2 8 = ?
$$
To what power must I raise 2 to get 8?
Since $2^3 = 8$, we say:
$$
\log_2 8 = 3
$$
$$ \log_b x = y \quad \text{means} \quad b^y = x $$
Logarithms are like the opposite of exponents. If: $$ 10^2 = 100, \quad \text{then} \quad \log_{10} 100 = 2 $$
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